Tuesday, 28 November 2017

8085 Program to Add contents of two memory locations in 8085 Processor

Add contents of two memory locations
Statement: Add the contents of memory locations 40001H and 4001H and place the result in the memory locations 4002Hand 4003H.
Sample problem:       

       (4000H) = 7FH
       (400lH)  = 89H
Result    = 7FH + 89H = lO8H
       (4002H) = 08H
       (4003H) = 0lH

Source program:

       LXI H, 4000H  : HL Points 4000H
       MOV A, M       : Get first operand
       INX H             : HL Points 4001H
       ADD M           : Add second operand
       INX H             : HL Points 4002H
       MOV M, A       : Store the lower byte of result at 4002H
       MVI A, 00       : Initialize higher byte result with 00H
       ADC A           : Add carry in the high byte result
       INX H             : HL Points 4003H
       MOV M, A       : Store the higher byte of result at 4003H
       HLT               : Terminate program execution

1 comments:

Technical GH said...

very well explain
i have also written some more about 8085
visit my site :http://www.technicalgh.com/2017/12/bus-structure-of-8085-microprocessor.html

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