Saturday, 11 November 2017

How to find smallest number in array in 8085

how to find smallest number in array in 8085


AIM:
     To find the smallest number in an array of data using 8085 instruction set.
    
ALGORITHM:
     1) Load the address of the first element of the array in HL pair
     2) Move the count to B – reg.
     3) Increment the pointer
     4) Get the first data in A – reg.
     5) Decrement the count.
     6) Increment the pointer
     7) Compare the content of memory addressed by HL pair with that of A - reg.
     8) If carry = 1, go to step 10 or if Carry = 0 go to step 9
     9) Move the content of memory addressed by HL to A – reg.
     10) Decrement the count
     11) Check for Zero of the count. If ZF = 0, go to step 6, or if ZF = 1 go to next step.
     12) Store the smallest data in memory.
     13) Terminate the program.
    
PROGRAM:
             LXI H,4200 Set pointer for array
             MOV B,M         Load the Count
             INX  H         Set 1st element as largest data
             MOV A,M
             DCR B         Decremented the count
LOOP:    INX H
             CMP M         If A- reg < M go to AHEAD
             JC AHEAD
             MOV A,M        Set the new value as smallest
AHEAD:DCR B
             JNZ LOOP   Repeat comparisons till count = 0
             STA 4300        Store the largest value at 4300
             HLT
OBSERVATION:
                   05 (4200) ----- Array Size
    Input:
                   0A (4201)
                   F1 (4202)
                   1F (4203)
                   26 (4204)
                   FE (4205)
                   0A (4300)
    Output:
   
RESULT:
Thus the program to find the smallest number in an array of data was executed

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