How to multiply two numbers in 8085 , 8085 multiplication program with explanation
MULTIPLICATION OF TWO 8 BIT NUMBERS
AIM:
To perform the multiplication of two 8 bit numbers using 8085.
ALGORITHM:
1) Start the program by loading HL register pair with address of memory location.
2) Move the data to a register (B register).
3) Get the second data and load into Accumulator.
Add the two register contents
4) Check for carry.
Increment the value of carry.
5) Check whether repeated addition is over and store the value of product and carry
in memory location.
6) Terminate the program.
PROGRAM:
MVI D,00 Initialize register D to 00
MVI A,00 Initialize Accumulator content to 00
LXI H,4150
MOV B,M Get the first number in B - reg
INX H
MOV C,M Get the second number in C- reg.LOOP: ADD B Add content of A - reg to register B.
JNC NEXT Jump on no carry to NEXT.
INR D Increment content of register DNEXT: DCR C Decrement content of register C.
JNZ LOOP Jump on no zero to address
STA 4152 Store the result in Memory
MOV A, D
STA 4153 Store the MSB of result in Memory HLT Terminate the program.
OBSERVATION:
FF (4150)
Input:
FF (4151)
01 (4152)
Output:
FE (4153)
RESULT:
Thus the program to multiply two 8-bit numbers was executed.
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